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8t^2+55t+8=0
a = 8; b = 55; c = +8;
Δ = b2-4ac
Δ = 552-4·8·8
Δ = 2769
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-\sqrt{2769}}{2*8}=\frac{-55-\sqrt{2769}}{16} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+\sqrt{2769}}{2*8}=\frac{-55+\sqrt{2769}}{16} $
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